Base | Representation |
---|---|
bin | 1100001110100000010001… |
… | …1100001011001001101011 |
3 | 1202121011120020022011211120 |
4 | 3003220010130023021223 |
5 | 3230223410431143201 |
6 | 44331435452230323 |
7 | 2555151024501441 |
oct | 303500434131153 |
9 | 52534506264746 |
10 | 13443322131051 |
11 | 431330a97038a |
12 | 16114a546b3a3 |
13 | 766913709717 |
14 | 346935a92b91 |
15 | 184a5953c536 |
hex | c3a0470b26b |
13443322131051 has 8 divisors (see below), whose sum is σ = 17925294210624. Its totient is φ = 8961782402760.
The previous prime is 13443322130999. The next prime is 13443322131181. The reversal of 13443322131051 is 15013122334431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13443322131051 - 213 = 13443322122859 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13443322131751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108015261 + ... + 108139646.
It is an arithmetic number, because the mean of its divisors is an integer number (2240661776328).
Almost surely, 213443322131051 is an apocalyptic number.
13443322131051 is a deficient number, since it is larger than the sum of its proper divisors (4481972079573).
13443322131051 is a wasteful number, since it uses less digits than its factorization.
13443322131051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 216175641.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 13443322131051 its reverse (15013122334431), we get a palindrome (28456444465482).
The spelling of 13443322131051 in words is "thirteen trillion, four hundred forty-three billion, three hundred twenty-two million, one hundred thirty-one thousand, fifty-one".
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