13443330055151 has 4 divisors (see below), whose sum is σ = 13499111507904. Its totient is φ = 13387548602400.

The previous prime is 13443330055123. The next prime is 13443330055153. The reversal of 13443330055151 is 15155003334431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13443330055151 - 2²² = 13443325860847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13443330055153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27890726015 + ... + 27890726496.

It is an arithmetic number, because the mean of its divisors is an integer number (3374777876976).

Almost surely, 2^{13443330055151} is an apocalyptic number.

13443330055151 is a deficient number, since it is larger than the sum of its proper divisors (55781452753).

13443330055151 is an equidigital number, since it uses as much as digits as its factorization.

13443330055151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55781452752.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 13443330055151 its reverse (15155003334431), we get a palindrome (28598333389582).

The spelling of 13443330055151 in words is "thirteen trillion, four hundred forty-three billion, three hundred thirty million, fifty-five thousand, one hundred fifty-one".