13443403542341 has 4 divisors (see below), whose sum is σ = 13729433404992. Its totient is φ = 13157373679692.

The previous prime is 13443403542319. The next prime is 13443403542343. The reversal of 13443403542341 is 14324530434431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13443403542341 - 2⁶ = 13443403542277 is a prime.

It is a super-3 number, since 3×13443403542341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13443403542343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143014931255 + ... + 143014931348.

It is an arithmetic number, because the mean of its divisors is an integer number (3432358351248).

Almost surely, 2^{13443403542341} is an apocalyptic number.

It is an amenable number.

13443403542341 is a deficient number, since it is larger than the sum of its proper divisors (286029862651).

13443403542341 is an equidigital number, since it uses as much as digits as its factorization.

13443403542341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 286029862650.

The product of its (nonzero) digits is 829440, while the sum is 41.

Adding to 13443403542341 its reverse (14324530434431), we get a palindrome (27767933976772).

The spelling of 13443403542341 in words is "thirteen trillion, four hundred forty-three billion, four hundred three million, five hundred forty-two thousand, three hundred forty-one".