Base | Representation |
---|---|
bin | 10011100100000000111… |
… | …100100110110101010101 |
3 | 11202111222102002220222102 |
4 | 103210000330212311111 |
5 | 134011202201320344 |
6 | 2505325341411445 |
7 | 166061004665363 |
oct | 23440074466525 |
9 | 4674872086872 |
10 | 1344340651349 |
11 | 47914a2838a3 |
12 | 198660b69b85 |
13 | 99a03530347 |
14 | 490d0422633 |
15 | 24e81a20e4e |
hex | 13900f26d55 |
1344340651349 has 2 divisors, whose sum is σ = 1344340651350. Its totient is φ = 1344340651348.
The previous prime is 1344340651327. The next prime is 1344340651373. The reversal of 1344340651349 is 9431560434431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1297792588849 + 46548062500 = 1139207^2 + 215750^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344340651349 - 212 = 1344340647253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344340651319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672170325674 + 672170325675.
It is an arithmetic number, because the mean of its divisors is an integer number (672170325675).
Almost surely, 21344340651349 is an apocalyptic number.
It is an amenable number.
1344340651349 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344340651349 is an equidigital number, since it uses as much as digits as its factorization.
1344340651349 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1866240, while the sum is 47.
The spelling of 1344340651349 in words is "one trillion, three hundred forty-four billion, three hundred forty million, six hundred fifty-one thousand, three hundred forty-nine".
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