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1344345411139 is a prime number
BaseRepresentation
bin10011100100000001001…
…110110000111001000011
311202111222202001202011221
4103210001032300321003
5134011204411124024
62505330031415511
7166061063311333
oct23440116607103
94674882052157
101344345411139
11479151a34a05
12198662684597
1399a045089a3
14490d0d010c3
1524e821613e4
hex139013b0e43

1344345411139 has 2 divisors, whose sum is σ = 1344345411140. Its totient is φ = 1344345411138.

The previous prime is 1344345411133. The next prime is 1344345411203. The reversal of 1344345411139 is 9311145434431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1344345411139 - 25 = 1344345411107 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1344345411095 and 1344345411104.

It is not a weakly prime, because it can be changed into another prime (1344345411133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672172705569 + 672172705570.

It is an arithmetic number, because the mean of its divisors is an integer number (672172705570).

Almost surely, 21344345411139 is an apocalyptic number.

1344345411139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344345411139 is an equidigital number, since it uses as much as digits as its factorization.

1344345411139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 311040, while the sum is 43.

The spelling of 1344345411139 in words is "one trillion, three hundred forty-four billion, three hundred forty-five million, four hundred eleven thousand, one hundred thirty-nine".