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13443525341 = 22360284867
BaseRepresentation
bin11001000010100101…
…11110101011011101
31021200220100211211222
430201102332223131
5210013020302331
610101553223125
7654100036301
oct144122765335
937626324758
1013443525341
115779579624
122732261aa5
13136324262c
1491761dd01
1553a361b7b
hex3214beadd

13443525341 has 4 divisors (see below), whose sum is σ = 13503810432. Its totient is φ = 13383240252.

The previous prime is 13443525257. The next prime is 13443525367. The reversal of 13443525341 is 14352534431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13443525341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13443525391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30142211 + ... + 30142656.

It is an arithmetic number, because the mean of its divisors is an integer number (3375952608).

Almost surely, 213443525341 is an apocalyptic number.

It is an amenable number.

13443525341 is a deficient number, since it is larger than the sum of its proper divisors (60285091).

13443525341 is an equidigital number, since it uses as much as digits as its factorization.

13443525341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60285090.

The product of its digits is 86400, while the sum is 35.

The spelling of 13443525341 in words is "thirteen billion, four hundred forty-three million, five hundred twenty-five thousand, three hundred forty-one".

Divisors: 1 223 60284867 13443525341