Base | Representation |
---|---|
bin | 11110100100011000010000… |
… | …100000101110100001010011 |
3 | 122122000110121101000022120202 |
4 | 132210120100200232201103 |
5 | 120110141332342022003 |
6 | 1153533300034525415 |
7 | 40214031550040015 |
oct | 3644302040564123 |
9 | 578013541008522 |
10 | 134441343314003 |
11 | 399232874709a0 |
12 | 130b3771a3686b |
13 | 5a029c216355b |
14 | 252add24261b5 |
15 | 10821db82d088 |
hex | 7a461082e853 |
134441343314003 has 16 divisors (see below), whose sum is σ = 153054146564352. Its totient is φ = 116894669892000.
The previous prime is 134441343313993. The next prime is 134441343314023. The reversal of 134441343314003 is 300413343144431.
It is not a de Polignac number, because 134441343314003 - 26 = 134441343313939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134441343314023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21917093 + ... + 27372278.
It is an arithmetic number, because the mean of its divisors is an integer number (9565884160272).
Almost surely, 2134441343314003 is an apocalyptic number.
134441343314003 is a deficient number, since it is larger than the sum of its proper divisors (18612803250349).
134441343314003 is a wasteful number, since it uses less digits than its factorization.
134441343314003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49300186.
The product of its (nonzero) digits is 248832, while the sum is 38.
Adding to 134441343314003 its reverse (300413343144431), we get a palindrome (434854686458434).
The spelling of 134441343314003 in words is "one hundred thirty-four trillion, four hundred forty-one billion, three hundred forty-three million, three hundred fourteen thousand, three".
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