Base | Representation |
---|---|
bin | 10011100100000101101… |
… | …100001001110110010001 |
3 | 11202112011221211122200111 |
4 | 103210011230021312101 |
5 | 134011333034140101 |
6 | 2505341303121321 |
7 | 166062662232652 |
oct | 23440554116621 |
9 | 4675157748614 |
10 | 1344420224401 |
11 | 479190193251 |
12 | 198683743241 |
13 | 99a16b712a7 |
14 | 490dac17529 |
15 | 24e889dd251 |
hex | 13905b09d91 |
1344420224401 has 4 divisors (see below), whose sum is σ = 1415179183600. Its totient is φ = 1273661265204.
The previous prime is 1344420224383. The next prime is 1344420224453. The reversal of 1344420224401 is 1044220244431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344420224401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1344420224501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35379479571 + ... + 35379479608.
It is an arithmetic number, because the mean of its divisors is an integer number (353794795900).
Almost surely, 21344420224401 is an apocalyptic number.
It is an amenable number.
1344420224401 is a deficient number, since it is larger than the sum of its proper divisors (70758959199).
1344420224401 is an equidigital number, since it uses as much as digits as its factorization.
1344420224401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70758959198.
The product of its (nonzero) digits is 24576, while the sum is 31.
Adding to 1344420224401 its reverse (1044220244431), we get a palindrome (2388640468832).
The spelling of 1344420224401 in words is "one trillion, three hundred forty-four billion, four hundred twenty million, two hundred twenty-four thousand, four hundred one".
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