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1344430344021 = 3448143448007
BaseRepresentation
bin10011100100000110010…
…010110000011101010101
311202112012122212210012020
4103210012102300131111
5134011343132002041
62505342304043353
7166063144241142
oct23440622603525
94675178783166
101344430344021
11479195975276
12198687003559
1399a18ca542b
14490dc2cd3c9
1524e8983b866
hex139064b0755

1344430344021 has 4 divisors (see below), whose sum is σ = 1792573792032. Its totient is φ = 896286896012.

The previous prime is 1344430344001. The next prime is 1344430344031. The reversal of 1344430344021 is 1204430344431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344430344021 - 25 = 1344430343989 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344430344001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224071724001 + ... + 224071724006.

It is an arithmetic number, because the mean of its divisors is an integer number (448143448008).

Almost surely, 21344430344021 is an apocalyptic number.

It is an amenable number.

1344430344021 is a deficient number, since it is larger than the sum of its proper divisors (448143448011).

1344430344021 is an equidigital number, since it uses as much as digits as its factorization.

1344430344021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448143448010.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 1344430344021 its reverse (1204430344431), we get a palindrome (2548860688452).

The spelling of 1344430344021 in words is "one trillion, three hundred forty-four billion, four hundred thirty million, three hundred forty-four thousand, twenty-one".

Divisors: 1 3 448143448007 1344430344021