1344444214121 has 2 divisors, whose sum is σ = 1344444214122. Its totient is φ = 1344444214120.

The previous prime is 1344444214097. The next prime is 1344444214123. The reversal of 1344444214121 is 1214124444431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1339426616896 + 5017597225 = 1157336^2 + 70835^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344444214121 - 2¹⁰ = 1344444213097 is a prime.

Together with 1344444214123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1344444214123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672222107060 + 672222107061.

It is an arithmetic number, because the mean of its divisors is an integer number (672222107061).

Almost surely, 2^{1344444214121} is an apocalyptic number.

It is an amenable number.

1344444214121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344444214121 is an equidigital number, since it uses as much as digits as its factorization.

1344444214121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 49152, while the sum is 35.

Adding to 1344444214121 its reverse (1214124444431), we get a palindrome (2558568658552).

The spelling of 1344444214121 in words is "one trillion, three hundred forty-four billion, four hundred forty-four million, two hundred fourteen thousand, one hundred twenty-one".