Base | Representation |
---|---|
bin | 11001000010101101… |
… | …01101100111000011 |
3 | 1021200222012120022201 |
4 | 30201112231213003 |
5 | 210013243112003 |
6 | 10102030214031 |
7 | 654111253450 |
oct | 144126554703 |
9 | 37628176281 |
10 | 13444504003 |
11 | 577a087937 |
12 | 2732654317 |
13 | 13634c5c18 |
14 | 9177d6827 |
15 | 53a4a6b1d |
hex | 3215ad9c3 |
13444504003 has 8 divisors (see below), whose sum is σ = 15367254272. Its totient is φ = 11522280456.
The previous prime is 13444503983. The next prime is 13444504033. The reversal of 13444504003 is 30040544431.
13444504003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13444504003 - 213 = 13444495811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13444504033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75375 + ... + 180472.
It is an arithmetic number, because the mean of its divisors is an integer number (1920906784).
Almost surely, 213444504003 is an apocalyptic number.
13444504003 is a deficient number, since it is larger than the sum of its proper divisors (1922750269).
13444504003 is an equidigital number, since it uses as much as digits as its factorization.
13444504003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263361.
The product of its (nonzero) digits is 11520, while the sum is 28.
The spelling of 13444504003 in words is "thirteen billion, four hundred forty-four million, five hundred four thousand, three".
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