Base | Representation |
---|---|
bin | 10011100100000111100… |
… | …001011001101010010111 |
3 | 11202112021002200012000212 |
4 | 103210013201121222113 |
5 | 134011413421210043 |
6 | 2505344322000035 |
7 | 166063514414123 |
oct | 23440741315227 |
9 | 4675232605025 |
10 | 1344450960023 |
11 | 4791a6576396 |
12 | 198691aa601b |
13 | 99a20343052 |
14 | 49100d38583 |
15 | 24e8b560018 |
hex | 13907859a97 |
1344450960023 has 2 divisors, whose sum is σ = 1344450960024. Its totient is φ = 1344450960022.
The previous prime is 1344450959987. The next prime is 1344450960031. The reversal of 1344450960023 is 3200690544431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344450960023 - 210 = 1344450958999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344450930023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672225480011 + 672225480012.
It is an arithmetic number, because the mean of its divisors is an integer number (672225480012).
Almost surely, 21344450960023 is an apocalyptic number.
1344450960023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344450960023 is an equidigital number, since it uses as much as digits as its factorization.
1344450960023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 1344450960023 in words is "one trillion, three hundred forty-four billion, four hundred fifty million, nine hundred sixty thousand, twenty-three".
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