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134447114051 = 220760918493
BaseRepresentation
bin111110100110110101…
…1000010011101000011
3110212000211222001020122
41331031223002131003
54200321430122201
6141433020130455
712466503420305
oct1751553023503
9425024861218
10134447114051
11520229887a8
1222082096a2b
13c8a8322473
146715d69975
15376d4a6e1b
hex1f4dac2743

134447114051 has 4 divisors (see below), whose sum is σ = 134508034752. Its totient is φ = 134386193352.

The previous prime is 134447114047. The next prime is 134447114093. The reversal of 134447114051 is 150411744431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150411744431 = 1311570134187.

It is a cyclic number.

It is not a de Polignac number, because 134447114051 - 22 = 134447114047 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134447114251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30457040 + ... + 30461453.

It is an arithmetic number, because the mean of its divisors is an integer number (33627008688).

Almost surely, 2134447114051 is an apocalyptic number.

134447114051 is a deficient number, since it is larger than the sum of its proper divisors (60920701).

134447114051 is an equidigital number, since it uses as much as digits as its factorization.

134447114051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60920700.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 134447114051 its reverse (150411744431), we get a palindrome (284858858482).

The spelling of 134447114051 in words is "one hundred thirty-four billion, four hundred forty-seven million, one hundred fourteen thousand, fifty-one".

Divisors: 1 2207 60918493 134447114051