13444779433 has 2 divisors, whose sum is σ = 13444779434. Its totient is φ = 13444779432.

The previous prime is 13444779389. The next prime is 13444779451. The reversal of 13444779433 is 33497744431.

13444779433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10843473424 + 2601306009 = 104132^2 + 51003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13444779433 is a prime.

It is not a weakly prime, because it can be changed into another prime (13444779833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722389716 + 6722389717.

It is an arithmetic number, because the mean of its divisors is an integer number (6722389717).

Almost surely, 2^13444779433 is an apocalyptic number.

It is an amenable number.

13444779433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13444779433 is an equidigital number, since it uses as much as digits as its factorization.

13444779433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3048192, while the sum is 49.

The spelling of 13444779433 in words is "thirteen billion, four hundred forty-four million, seven hundred seventy-nine thousand, four hundred thirty-three".