Base | Representation |
---|---|
bin | 1100001110100110111010… |
… | …0110001001011011100111 |
3 | 1202121100011100120022120022 |
4 | 3003221232212021123213 |
5 | 3230241032400132333 |
6 | 44332332313225355 |
7 | 2555243121651263 |
oct | 303515646113347 |
9 | 52540140508508 |
10 | 13445103130343 |
11 | 4314044227525 |
12 | 1611901a0225b |
13 | 766b386a6161 |
14 | 346a644210a3 |
15 | 184b10a90c98 |
hex | c3a6e9896e7 |
13445103130343 has 2 divisors, whose sum is σ = 13445103130344. Its totient is φ = 13445103130342.
The previous prime is 13445103130289. The next prime is 13445103130351. The reversal of 13445103130343 is 34303130154431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13445103130343 - 216 = 13445103064807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13445103130243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722551565171 + 6722551565172.
It is an arithmetic number, because the mean of its divisors is an integer number (6722551565172).
Almost surely, 213445103130343 is an apocalyptic number.
13445103130343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13445103130343 is an equidigital number, since it uses as much as digits as its factorization.
13445103130343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 13445103130343 its reverse (34303130154431), we get a palindrome (47748233284774).
The spelling of 13445103130343 in words is "thirteen trillion, four hundred forty-five billion, one hundred three million, one hundred thirty thousand, three hundred forty-three".
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