Base | Representation |
---|---|
bin | 111110100111000101… |
… | …0101010111000100101 |
3 | 110212001102120022211012 |
4 | 1331032022222320211 |
5 | 4200331040443432 |
6 | 141433513552005 |
7 | 12466634044364 |
oct | 1751612527045 |
9 | 425042508735 |
10 | 134455406117 |
11 | 5202763174a |
12 | 22084a15605 |
13 | c8a9c66806 |
14 | 67170c77db |
15 | 376e093cb2 |
hex | 1f4e2aae25 |
134455406117 has 2 divisors, whose sum is σ = 134455406118. Its totient is φ = 134455406116.
The previous prime is 134455406089. The next prime is 134455406123. The reversal of 134455406117 is 711604554431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111749135521 + 22706270596 = 334289^2 + 150686^2 .
It is a cyclic number.
It is not a de Polignac number, because 134455406117 - 210 = 134455405093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134455408117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67227703058 + 67227703059.
It is an arithmetic number, because the mean of its divisors is an integer number (67227703059).
Almost surely, 2134455406117 is an apocalyptic number.
It is an amenable number.
134455406117 is a deficient number, since it is larger than the sum of its proper divisors (1).
134455406117 is an equidigital number, since it uses as much as digits as its factorization.
134455406117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 134455406117 in words is "one hundred thirty-four billion, four hundred fifty-five million, four hundred six thousand, one hundred seventeen".
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