Base | Representation |
---|---|
bin | 1100001110110101001111… |
… | …0101110010001111111111 |
3 | 1202121201002101122111221222 |
4 | 3003231103311302033333 |
5 | 3230321421444242114 |
6 | 44334210104143555 |
7 | 2555440333055636 |
oct | 303552365621777 |
9 | 52551071574858 |
10 | 13448949212159 |
11 | 431573824273a |
12 | 16125b5a67bbb |
13 | 7672cc456406 |
14 | 346d0b14a51d |
15 | 184c8856098e |
hex | c3b53d723ff |
13448949212159 has 2 divisors, whose sum is σ = 13448949212160. Its totient is φ = 13448949212158.
The previous prime is 13448949212143. The next prime is 13448949212239. The reversal of 13448949212159 is 95121294984431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13448949212159 - 24 = 13448949212143 is a prime.
It is a super-2 number, since 2×134489492121592 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13448949212059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6724474606079 + 6724474606080.
It is an arithmetic number, because the mean of its divisors is an integer number (6724474606080).
Almost surely, 213448949212159 is an apocalyptic number.
13448949212159 is a deficient number, since it is larger than the sum of its proper divisors (1).
13448949212159 is an equidigital number, since it uses as much as digits as its factorization.
13448949212159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 22394880, while the sum is 62.
The spelling of 13448949212159 in words is "thirteen trillion, four hundred forty-eight billion, nine hundred forty-nine million, two hundred twelve thousand, one hundred fifty-nine".
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