Base | Representation |
---|---|
bin | 11001000011010011… |
… | …01111101110000101 |
3 | 1021201022121001110111 |
4 | 30201221233232011 |
5 | 210021032242011 |
6 | 10102325153021 |
7 | 654201543652 |
oct | 144151575605 |
9 | 37638531414 |
10 | 13449493381 |
11 | 5781985495 |
12 | 273425b771 |
13 | 1364551c0c |
14 | 918334c29 |
15 | 53ab40121 |
hex | 321a6fb85 |
13449493381 has 2 divisors, whose sum is σ = 13449493382. Its totient is φ = 13449493380.
The previous prime is 13449493361. The next prime is 13449493397. The reversal of 13449493381 is 18339494431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13355500356 + 93993025 = 115566^2 + 9695^2 .
It is a cyclic number.
It is not a de Polignac number, because 13449493381 - 215 = 13449460613 is a prime.
It is a super-2 number, since 2×134494933812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13449493361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6724746690 + 6724746691.
It is an arithmetic number, because the mean of its divisors is an integer number (6724746691).
Almost surely, 213449493381 is an apocalyptic number.
It is an amenable number.
13449493381 is a deficient number, since it is larger than the sum of its proper divisors (1).
13449493381 is an equidigital number, since it uses as much as digits as its factorization.
13449493381 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1119744, while the sum is 49.
The spelling of 13449493381 in words is "thirteen billion, four hundred forty-nine million, four hundred ninety-three thousand, three hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •