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13449965821141 = 47364728396603
BaseRepresentation
bin1100001110111001000001…
…1011110101110011010101
31202121210201020120121022111
43003232100123311303111
53230331012222234031
644334455021431021
72555504456103343
oct303562033656325
952553636517274
1013449965821141
11431610a080053
12161283a40b471
13767431c5a3a5
14346da617c993
15184ce79231b1
hexc3b906f5cd5

13449965821141 has 4 divisors (see below), whose sum is σ = 13449994691392. Its totient is φ = 13449936950892.

The previous prime is 13449965821093. The next prime is 13449965821177. The reversal of 13449965821141 is 14112856994431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13449965821141 - 27 = 13449965821013 is a prime.

It is a super-2 number, since 2×134499658211412 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13449965822141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13724655 + ... + 14671948.

It is an arithmetic number, because the mean of its divisors is an integer number (3362498672848).

Almost surely, 213449965821141 is an apocalyptic number.

It is an amenable number.

13449965821141 is a deficient number, since it is larger than the sum of its proper divisors (28870251).

13449965821141 is an equidigital number, since it uses as much as digits as its factorization.

13449965821141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28870250.

The product of its digits is 7464960, while the sum is 58.

The spelling of 13449965821141 in words is "thirteen trillion, four hundred forty-nine billion, nine hundred sixty-five million, eight hundred twenty-one thousand, one hundred forty-one".

Divisors: 1 473647 28396603 13449965821141