Base | Representation |
---|---|
bin | 11001000011011001… |
… | …11001011010100111 |
3 | 1021201101011000201111 |
4 | 30201230321122213 |
5 | 210021240211102 |
6 | 10102355005451 |
7 | 654211554361 |
oct | 144154713247 |
9 | 37641130644 |
10 | 13450319527 |
11 | 578239a157 |
12 | 2734599887 |
13 | 1364780c68 |
14 | 9184abd31 |
15 | 53ac54cd7 |
hex | 321b396a7 |
13450319527 has 2 divisors, whose sum is σ = 13450319528. Its totient is φ = 13450319526.
The previous prime is 13450319473. The next prime is 13450319537. The reversal of 13450319527 is 72591305431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13450319527 - 223 = 13441930919 is a prime.
It is a super-2 number, since 2×134503195272 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13450319527.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13450319537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725159763 + 6725159764.
It is an arithmetic number, because the mean of its divisors is an integer number (6725159764).
Almost surely, 213450319527 is an apocalyptic number.
13450319527 is a deficient number, since it is larger than the sum of its proper divisors (1).
13450319527 is an equidigital number, since it uses as much as digits as its factorization.
13450319527 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 13450319527 in words is "thirteen billion, four hundred fifty million, three hundred nineteen thousand, five hundred twenty-seven".
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