1345032340111 has 8 divisors (see below), whose sum is σ = 1364190380784. Its totient is φ = 1325944605120.

The previous prime is 1345032340087. The next prime is 1345032340129. The reversal of 1345032340111 is 1110432305431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1345032340111 - 2⁵ = 1345032340079 is a prime.

It is a super-2 number, since 2×1345032340111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1345032340111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345032340151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17537886 + ... + 17614411.

It is an arithmetic number, because the mean of its divisors is an integer number (170523797598).

Almost surely, 2^{1345032340111} is an apocalyptic number.

1345032340111 is a deficient number, since it is larger than the sum of its proper divisors (19158040673).

1345032340111 is an equidigital number, since it uses as much as digits as its factorization.

1345032340111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35152841.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1345032340111 its reverse (1110432305431), we get a palindrome (2455464645542).

The spelling of 1345032340111 in words is "one trillion, three hundred forty-five billion, thirty-two million, three hundred forty thousand, one hundred eleven".