1345061614081 has 2 divisors, whose sum is σ = 1345061614082. Its totient is φ = 1345061614080.

The previous prime is 1345061614049. The next prime is 1345061614121. The reversal of 1345061614081 is 1804161605431.

It is an a-pointer prime, because the next prime (1345061614121) can be obtained adding 1345061614081 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1341207191025 + 3854423056 = 1158105^2 + 62084^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345061614081 - 2⁵ = 1345061614049 is a prime.

It is a super-2 number, since 2×1345061614081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1345061611081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672530807040 + 672530807041.

It is an arithmetic number, because the mean of its divisors is an integer number (672530807041).

Almost surely, 2^{1345061614081} is an apocalyptic number.

It is an amenable number.

1345061614081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345061614081 is an equidigital number, since it uses as much as digits as its factorization.

1345061614081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 40.

The spelling of 1345061614081 in words is "one trillion, three hundred forty-five billion, sixty-one million, six hundred fourteen thousand, eighty-one".