Search a number
-
+
13451012240541 = 34483670746847
BaseRepresentation
bin1100001110111100111011…
…0011100111010010011101
31202121220102011121012212120
43003233032303213102131
53230340133113144131
644335150522053153
72555542423366641
oct303571663472235
952556364535776
1013451012240541
1143165a6819477
121612a9094a1b9
1376756a99ac75
14347065130c21
15184d59723496
hexc3bcece749d

13451012240541 has 4 divisors (see below), whose sum is σ = 17934682987392. Its totient is φ = 8967341493692.

The previous prime is 13451012240539. The next prime is 13451012240551. The reversal of 13451012240541 is 14504221015431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13451012240541 - 21 = 13451012240539 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13451012240551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2241835373421 + ... + 2241835373426.

It is an arithmetic number, because the mean of its divisors is an integer number (4483670746848).

Almost surely, 213451012240541 is an apocalyptic number.

It is an amenable number.

13451012240541 is a deficient number, since it is larger than the sum of its proper divisors (4483670746851).

13451012240541 is an equidigital number, since it uses as much as digits as its factorization.

13451012240541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4483670746850.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 13451012240541 its reverse (14504221015431), we get a palindrome (27955233255972).

The spelling of 13451012240541 in words is "thirteen trillion, four hundred fifty-one billion, twelve million, two hundred forty thousand, five hundred forty-one".

Divisors: 1 3 4483670746847 13451012240541