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1345114134431 is a prime number
BaseRepresentation
bin10011100100101111000…
…011001101011110011111
311202120222022112221021222
4103210233003031132133
5134014243204300211
62505534212043555
7166116116331164
oct23445703153637
94676868487258
101345114134431
11479506953111
121988380035bb
1399ac785a742
144916504806b
1524ec98ab1db
hex1392f0cd79f

1345114134431 has 2 divisors, whose sum is σ = 1345114134432. Its totient is φ = 1345114134430.

The previous prime is 1345114134407. The next prime is 1345114134457. The reversal of 1345114134431 is 1344314115431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1345114134431 is a prime.

It is a super-2 number, since 2×13451141344312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1345114134391 and 1345114134400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1345114134731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672557067215 + 672557067216.

It is an arithmetic number, because the mean of its divisors is an integer number (672557067216).

Almost surely, 21345114134431 is an apocalyptic number.

1345114134431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1345114134431 is an equidigital number, since it uses as much as digits as its factorization.

1345114134431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 35.

Adding to 1345114134431 its reverse (1344314115431), we get a palindrome (2689428249862).

The spelling of 1345114134431 in words is "one trillion, three hundred forty-five billion, one hundred fourteen million, one hundred thirty-four thousand, four hundred thirty-one".