Base | Representation |
---|---|
bin | 11001000011100000… |
… | …10101010001001111 |
3 | 1021201102211210000002 |
4 | 30201300111101033 |
5 | 210022003020142 |
6 | 10102430154515 |
7 | 654222324656 |
oct | 144160252117 |
9 | 37642753002 |
10 | 13451220047 |
11 | 5782954791 |
12 | 2734952a3b |
13 | 1364a07b05 |
14 | 91866419d |
15 | 53ad81a32 |
hex | 321c1544f |
13451220047 has 2 divisors, whose sum is σ = 13451220048. Its totient is φ = 13451220046.
The previous prime is 13451220011. The next prime is 13451220067. The reversal of 13451220047 is 74002215431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13451220047 - 218 = 13450957903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13451220067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6725610023 + 6725610024.
It is an arithmetic number, because the mean of its divisors is an integer number (6725610024).
Almost surely, 213451220047 is an apocalyptic number.
13451220047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13451220047 is an equidigital number, since it uses as much as digits as its factorization.
13451220047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 13451220047 its reverse (74002215431), we get a palindrome (87453435478).
The spelling of 13451220047 in words is "thirteen billion, four hundred fifty-one million, two hundred twenty thousand, forty-seven".
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