Base | Representation |
---|---|
bin | 111110101001000100… |
… | …0110000000111110011 |
3 | 110212020001220021010012 |
4 | 1331102020300013303 |
5 | 4201000113342042 |
6 | 141444253325135 |
7 | 12501403144145 |
oct | 1752210600763 |
9 | 425201807105 |
10 | 134522012147 |
11 | 52061194856 |
12 | 220a31967ab |
13 | c8ba9b7573 |
14 | 6721ca4c95 |
15 | 3774d4de82 |
hex | 1f522301f3 |
134522012147 has 2 divisors, whose sum is σ = 134522012148. Its totient is φ = 134522012146.
The previous prime is 134522012123. The next prime is 134522012153. The reversal of 134522012147 is 741210225431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134522012147 - 214 = 134521995763 is a prime.
It is not a weakly prime, because it can be changed into another prime (134522012047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67261006073 + 67261006074.
It is an arithmetic number, because the mean of its divisors is an integer number (67261006074).
Almost surely, 2134522012147 is an apocalyptic number.
134522012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
134522012147 is an equidigital number, since it uses as much as digits as its factorization.
134522012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 134522012147 its reverse (741210225431), we get a palindrome (875732237578).
The spelling of 134522012147 in words is "one hundred thirty-four billion, five hundred twenty-two million, twelve thousand, one hundred forty-seven".
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