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13452432025 = 52538097281
BaseRepresentation
bin11001000011101001…
…11101001010011001
31021201112010100112011
430201310331022121
5210022310311100
610102512145521
7654235533304
oct144164751231
937645110464
1013452432025
11578360231a
1227352382a1
131365040666
1491889bb3b
1553b020bba
hex321d3d299

13452432025 has 6 divisors (see below), whose sum is σ = 16681015742. Its totient is φ = 10761945600.

The previous prime is 13452432013. The next prime is 13452432031. The reversal of 13452432025 is 52023425431.

13452432025 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 816873561 + 12635558464 = 28581^2 + 112408^2 .

It is not a de Polignac number, because 13452432025 - 233 = 4862497433 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 269048616 + ... + 269048665.

Almost surely, 213452432025 is an apocalyptic number.

It is an amenable number.

13452432025 is a deficient number, since it is larger than the sum of its proper divisors (3228583717).

13452432025 is an equidigital number, since it uses as much as digits as its factorization.

13452432025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 538097291 (or 538097286 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 13452432025 its reverse (52023425431), we get a palindrome (65475857456).

The spelling of 13452432025 in words is "thirteen billion, four hundred fifty-two million, four hundred thirty-two thousand, twenty-five".

Divisors: 1 5 25 538097281 2690486405 13452432025