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13452522497 is a prime number
BaseRepresentation
bin11001000011101010…
…10011010000000001
31021201112021221121222
430201311103100001
5210022321204442
610102514124425
7654236361131
oct144165232001
937645257558
1013452522497
115783664297
122735280715
1313650728ab
149188c2ac1
1553b03c8d2
hex321d53401

13452522497 has 2 divisors, whose sum is σ = 13452522498. Its totient is φ = 13452522496.

The previous prime is 13452522491. The next prime is 13452522511. The reversal of 13452522497 is 79422525431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13398294001 + 54228496 = 115751^2 + 7364^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13452522497 is a prime.

It is a super-2 number, since 2×134525224972 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13452522491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726261248 + 6726261249.

It is an arithmetic number, because the mean of its divisors is an integer number (6726261249).

Almost surely, 213452522497 is an apocalyptic number.

It is an amenable number.

13452522497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13452522497 is an equidigital number, since it uses as much as digits as its factorization.

13452522497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 604800, while the sum is 44.

The spelling of 13452522497 in words is "thirteen billion, four hundred fifty-two million, five hundred twenty-two thousand, four hundred ninety-seven".