Base | Representation |
---|---|
bin | 111110101001001100… |
… | …1010001001101110001 |
3 | 110212020101001020120011 |
4 | 1331102121101031301 |
5 | 4201002220421001 |
6 | 141444530214521 |
7 | 12501455016502 |
oct | 1752231211561 |
9 | 425211036504 |
10 | 134526342001 |
11 | 52063681947 |
12 | 220a4724441 |
13 | c8bb8722cc |
14 | 67226b0ba9 |
15 | 3775406d51 |
hex | 1f52651371 |
134526342001 has 2 divisors, whose sum is σ = 134526342002. Its totient is φ = 134526342000.
The previous prime is 134526341941. The next prime is 134526342061. The reversal of 134526342001 is 100243625431.
It is a balanced prime because it is at equal distance from previous prime (134526341941) and next prime (134526342061).
It can be written as a sum of positive squares in only one way, i.e., 126839261025 + 7687080976 = 356145^2 + 87676^2 .
It is a cyclic number.
It is not a de Polignac number, because 134526342001 - 211 = 134526339953 is a prime.
It is not a weakly prime, because it can be changed into another prime (134526342061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67263171000 + 67263171001.
It is an arithmetic number, because the mean of its divisors is an integer number (67263171001).
Almost surely, 2134526342001 is an apocalyptic number.
It is an amenable number.
134526342001 is a deficient number, since it is larger than the sum of its proper divisors (1).
134526342001 is an equidigital number, since it uses as much as digits as its factorization.
134526342001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 134526342001 its reverse (100243625431), we get a palindrome (234769967432).
The spelling of 134526342001 in words is "one hundred thirty-four billion, five hundred twenty-six million, three hundred forty-two thousand, one".
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