Base | Representation |
---|---|
bin | 111110101001010011… |
… | …1101001011110111111 |
3 | 110212020122010202020101 |
4 | 1331102213221132333 |
5 | 4201004202031143 |
6 | 141445143101531 |
7 | 12501532036201 |
oct | 1752247513677 |
9 | 425218122211 |
10 | 134530111423 |
11 | 52065816974 |
12 | 220a5a418a7 |
13 | c8bc591c36 |
14 | 6722db2771 |
15 | 37758edb4d |
hex | 1f529e97bf |
134530111423 has 2 divisors, whose sum is σ = 134530111424. Its totient is φ = 134530111422.
The previous prime is 134530111393. The next prime is 134530111433. The reversal of 134530111423 is 324111035431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134530111423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134530111391 and 134530111400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134530111433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67265055711 + 67265055712.
It is an arithmetic number, because the mean of its divisors is an integer number (67265055712).
Almost surely, 2134530111423 is an apocalyptic number.
134530111423 is a deficient number, since it is larger than the sum of its proper divisors (1).
134530111423 is an equidigital number, since it uses as much as digits as its factorization.
134530111423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 134530111423 its reverse (324111035431), we get a palindrome (458641146854).
The spelling of 134530111423 in words is "one hundred thirty-four billion, five hundred thirty million, one hundred eleven thousand, four hundred twenty-three".
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