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1345323004042 = 212292194324943
BaseRepresentation
bin10011100100111011011…
…111111111000010001010
311202121111212120121112111
4103210323133333002022
5134020210142112132
62510011032532534
7166124233566403
oct23447337770212
94677455517474
101345323004042
11479603843a26
12198895b5114a
1399b2bbcbc24
1449184a989aa
1524edcdb8647
hex1393b7ff08a

1345323004042 has 16 divisors (see below), whose sum is σ = 2019799491840. Its totient is φ = 672056602992.

The previous prime is 1345323003889. The next prime is 1345323004061. The reversal of 1345323004042 is 2404003235431.

It is a happy number.

It is a super-2 number, since 2×13453230040422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1345323003995 and 1345323004013.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53923423 + ... + 53948365.

It is an arithmetic number, because the mean of its divisors is an integer number (126237468240).

Almost surely, 21345323004042 is an apocalyptic number.

1345323004042 is a deficient number, since it is larger than the sum of its proper divisors (674476487798).

1345323004042 is a wasteful number, since it uses less digits than its factorization.

1345323004042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48117.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 1345323004042 its reverse (2404003235431), we get a palindrome (3749326239473).

The spelling of 1345323004042 in words is "one trillion, three hundred forty-five billion, three hundred twenty-three million, four thousand, forty-two".

Divisors: 1 2 1229 2458 21943 24943 43886 49886 26967947 30654947 53935894 61309894 547324249 1094648498 672661502021 1345323004042