Base | Representation |
---|---|
bin | 10011100100111011011… |
… | …111111111000010001001 |
3 | 11202121111212120121112110 |
4 | 103210323133333002021 |
5 | 134020210142112131 |
6 | 2510011032532533 |
7 | 166124233566402 |
oct | 23447337770211 |
9 | 4677455517473 |
10 | 1345323004041 |
11 | 479603843a25 |
12 | 198895b51149 |
13 | 99b2bbcbc23 |
14 | 49184a989a9 |
15 | 24edcdb8646 |
hex | 1393b7ff089 |
1345323004041 has 8 divisors (see below), whose sum is σ = 1831929197184. Its totient is φ = 877799406800.
The previous prime is 1345323003889. The next prime is 1345323004061. The reversal of 1345323004041 is 1404003235431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1345323004041 - 211 = 1345323001993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1345323004061) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4770648810 + ... + 4770649091.
It is an arithmetic number, because the mean of its divisors is an integer number (228991149648).
Almost surely, 21345323004041 is an apocalyptic number.
It is an amenable number.
1345323004041 is a deficient number, since it is larger than the sum of its proper divisors (486606193143).
1345323004041 is an equidigital number, since it uses as much as digits as its factorization.
1345323004041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9541297951.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 1345323004041 its reverse (1404003235431), we get a palindrome (2749326239472).
The spelling of 1345323004041 in words is "one trillion, three hundred forty-five billion, three hundred twenty-three million, four thousand, forty-one".
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