Base | Representation |
---|---|
bin | 11001000011110001… |
… | …01001110110010011 |
3 | 1021201120221121101022 |
4 | 30201320221312103 |
5 | 210023032321431 |
6 | 10102545030055 |
7 | 654250011605 |
oct | 144170516623 |
9 | 37646847338 |
10 | 13453401491 |
11 | 5784104732 |
12 | 273562532b |
13 | 13652bc9ca |
14 | 918a71175 |
15 | 53b16307b |
hex | 321e29d93 |
13453401491 has 2 divisors, whose sum is σ = 13453401492. Its totient is φ = 13453401490.
The previous prime is 13453401389. The next prime is 13453401527. The reversal of 13453401491 is 19410435431.
13453401491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13453401491 is a prime.
It is not a weakly prime, because it can be changed into another prime (13453404491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6726700745 + 6726700746.
It is an arithmetic number, because the mean of its divisors is an integer number (6726700746).
Almost surely, 213453401491 is an apocalyptic number.
13453401491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13453401491 is an equidigital number, since it uses as much as digits as its factorization.
13453401491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 13453401491 in words is "thirteen billion, four hundred fifty-three million, four hundred one thousand, four hundred ninety-one".
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