13454062166353 has 4 divisors (see below), whose sum is σ = 13472169922368. Its totient is φ = 13435954410340.

The previous prime is 13454062166327. The next prime is 13454062166393. The reversal of 13454062166353 is 35366126045431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13454062166353 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13454062166297 and 13454062166306.

It is not an unprimeable number, because it can be changed into a prime (13454062166323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9053876893 + ... + 9053878378.

It is an arithmetic number, because the mean of its divisors is an integer number (3368042480592).

Almost surely, 2^{13454062166353} is an apocalyptic number.

It is an amenable number.

13454062166353 is a deficient number, since it is larger than the sum of its proper divisors (18107756015).

13454062166353 is an equidigital number, since it uses as much as digits as its factorization.

13454062166353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18107756014.

The product of its (nonzero) digits is 4665600, while the sum is 49.

The spelling of 13454062166353 in words is "thirteen trillion, four hundred fifty-four billion, sixty-two million, one hundred sixty-six thousand, three hundred fifty-three".