Base | Representation |
---|---|
bin | 11110100101110101010001… |
… | …000111010100011010110011 |
3 | 122122101000101100110202201221 |
4 | 132211311101013110122303 |
5 | 120113310400110422324 |
6 | 1154051213531005511 |
7 | 40224165432656623 |
oct | 3645652107243263 |
9 | 578330340422657 |
10 | 134541211420339 |
11 | 39961675401369 |
12 | 1310aba3599897 |
13 | 5a0c2495435b9 |
14 | 2531b87b52883 |
15 | 1084ad41b30e4 |
hex | 7a5d511d46b3 |
134541211420339 has 2 divisors, whose sum is σ = 134541211420340. Its totient is φ = 134541211420338.
The previous prime is 134541211420303. The next prime is 134541211420373. The reversal of 134541211420339 is 933024112145431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134541211420339 - 29 = 134541211419827 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134541211420295 and 134541211420304.
It is not a weakly prime, because it can be changed into another prime (134541211480339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67270605710169 + 67270605710170.
It is an arithmetic number, because the mean of its divisors is an integer number (67270605710170).
Almost surely, 2134541211420339 is an apocalyptic number.
134541211420339 is a deficient number, since it is larger than the sum of its proper divisors (1).
134541211420339 is an equidigital number, since it uses as much as digits as its factorization.
134541211420339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 134541211420339 in words is "one hundred thirty-four trillion, five hundred forty-one billion, two hundred eleven million, four hundred twenty thousand, three hundred thirty-nine".
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