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134541211420339 is a prime number
BaseRepresentation
bin11110100101110101010001…
…000111010100011010110011
3122122101000101100110202201221
4132211311101013110122303
5120113310400110422324
61154051213531005511
740224165432656623
oct3645652107243263
9578330340422657
10134541211420339
1139961675401369
121310aba3599897
135a0c2495435b9
142531b87b52883
151084ad41b30e4
hex7a5d511d46b3

134541211420339 has 2 divisors, whose sum is σ = 134541211420340. Its totient is φ = 134541211420338.

The previous prime is 134541211420303. The next prime is 134541211420373. The reversal of 134541211420339 is 933024112145431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134541211420339 - 29 = 134541211419827 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134541211420295 and 134541211420304.

It is not a weakly prime, because it can be changed into another prime (134541211480339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67270605710169 + 67270605710170.

It is an arithmetic number, because the mean of its divisors is an integer number (67270605710170).

Almost surely, 2134541211420339 is an apocalyptic number.

134541211420339 is a deficient number, since it is larger than the sum of its proper divisors (1).

134541211420339 is an equidigital number, since it uses as much as digits as its factorization.

134541211420339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 134541211420339 in words is "one hundred thirty-four trillion, five hundred forty-one billion, two hundred eleven million, four hundred twenty thousand, three hundred thirty-nine".