1345423243141 has 4 divisors (see below), whose sum is σ = 1416234992800. Its totient is φ = 1274611493484.

The previous prime is 1345423243117. The next prime is 1345423243193. The reversal of 1345423243141 is 1413423245431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1345423243141 - 2¹¹ = 1345423241093 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1345423243141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345423243841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35405874801 + ... + 35405874838.

It is an arithmetic number, because the mean of its divisors is an integer number (354058748200).

Almost surely, 2^{1345423243141} is an apocalyptic number.

It is an amenable number.

1345423243141 is a deficient number, since it is larger than the sum of its proper divisors (70811749659).

1345423243141 is an equidigital number, since it uses as much as digits as its factorization.

1345423243141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70811749658.

The product of its digits is 138240, while the sum is 37.

Adding to 1345423243141 its reverse (1413423245431), we get a palindrome (2758846488572).

The spelling of 1345423243141 in words is "one trillion, three hundred forty-five billion, four hundred twenty-three million, two hundred forty-three thousand, one hundred forty-one".