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1345454250035 = 5738441550001
BaseRepresentation
bin10011100101000011010…
…100101001100000110011
311202121212000112121012012
4103211003110221200303
5134020442242000120
62510032041553135
7166130416266650
oct23450324514063
94677760477165
101345454250035
11479670936a95
12198911aa57ab
1399b5016288c
14491982a0c27
1524ee96911c5
hex13943529833

1345454250035 has 8 divisors (see below), whose sum is σ = 1845194400096. Its totient is φ = 922597200000.

The previous prime is 1345454250017. The next prime is 1345454250047. The reversal of 1345454250035 is 5300524545431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1345454250035 - 28 = 1345454249779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1345454249974 and 1345454250001.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19220774966 + ... + 19220775035.

It is an arithmetic number, because the mean of its divisors is an integer number (230649300012).

Almost surely, 21345454250035 is an apocalyptic number.

1345454250035 is a deficient number, since it is larger than the sum of its proper divisors (499740150061).

1345454250035 is an equidigital number, since it uses as much as digits as its factorization.

1345454250035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38441550013.

The product of its (nonzero) digits is 720000, while the sum is 41.

Adding to 1345454250035 its reverse (5300524545431), we get a palindrome (6645978795466).

The spelling of 1345454250035 in words is "one trillion, three hundred forty-five billion, four hundred fifty-four million, two hundred fifty thousand, thirty-five".

Divisors: 1 5 7 35 38441550001 192207750005 269090850007 1345454250035