Base | Representation |
---|---|
bin | 111110101001110100… |
… | …1000000000111110111 |
3 | 110212021211101011001011 |
4 | 1331103221000013313 |
5 | 4201023043243021 |
6 | 141450554213051 |
7 | 12502130462032 |
oct | 1752351000767 |
9 | 425254334034 |
10 | 134547243511 |
11 | 5207445851a |
12 | 220ab724187 |
13 | c8c2cacb75 |
14 | 6725392019 |
15 | 3777184de1 |
hex | 1f53a401f7 |
134547243511 has 4 divisors (see below), whose sum is σ = 141628677400. Its totient is φ = 127465809624.
The previous prime is 134547243503. The next prime is 134547243533. The reversal of 134547243511 is 115342745431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 115342745431 = 277 ⋅416399803.
It is a cyclic number.
It is not a de Polignac number, because 134547243511 - 23 = 134547243503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134547643511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3540716916 + ... + 3540716953.
It is an arithmetic number, because the mean of its divisors is an integer number (35407169350).
Almost surely, 2134547243511 is an apocalyptic number.
134547243511 is a deficient number, since it is larger than the sum of its proper divisors (7081433889).
134547243511 is an equidigital number, since it uses as much as digits as its factorization.
134547243511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7081433888.
The product of its digits is 201600, while the sum is 40.
Adding to 134547243511 its reverse (115342745431), we get a palindrome (249889988942).
The spelling of 134547243511 in words is "one hundred thirty-four billion, five hundred forty-seven million, two hundred forty-three thousand, five hundred eleven".
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