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13455045193 is a prime number
BaseRepresentation
bin11001000011111101…
…11011001001001001
31021201201001010010011
430201332323021021
5210023442421233
610103044151521
7654266666002
oct144176731111
937651033104
1013455045193
115785027667
1227360985a1
131365746c05
14918d7c1a9
1553b38a0cd
hex321fbb249

13455045193 has 2 divisors, whose sum is σ = 13455045194. Its totient is φ = 13455045192.

The previous prime is 13455045139. The next prime is 13455045217. The reversal of 13455045193 is 39154055431.

It is a happy number.

Together with previous prime (13455045139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12750248889 + 704796304 = 112917^2 + 26548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13455045193 is a prime.

It is a super-2 number, since 2×134550451932 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13455445193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6727522596 + 6727522597.

It is an arithmetic number, because the mean of its divisors is an integer number (6727522597).

Almost surely, 213455045193 is an apocalyptic number.

It is an amenable number.

13455045193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13455045193 is an equidigital number, since it uses as much as digits as its factorization.

13455045193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 40.

The spelling of 13455045193 in words is "thirteen billion, four hundred fifty-five million, forty-five thousand, one hundred ninety-three".