1345543433 has 4 divisors (see below), whose sum is σ = 1449046788. Its totient is φ = 1242040080.

The previous prime is 1345543427. The next prime is 1345543469. The reversal of 1345543433 is 3343455431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3343455431 = 31 ⋅107853401.

It can be written as a sum of positive squares in 2 ways, for example, as 137077264 + 1208466169 = 11708^2 + 34763^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345543433 - 2²⁴ = 1328766217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1345543393 and 1345543402.

It is not an unprimeable number, because it can be changed into a prime (1345543483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51751658 + ... + 51751683.

It is an arithmetic number, because the mean of its divisors is an integer number (362261697).

Almost surely, 2^1345543433 is an apocalyptic number.

1345543433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1345543433 is a deficient number, since it is larger than the sum of its proper divisors (103503355).

1345543433 is a wasteful number, since it uses less digits than its factorization.

1345543433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103503354.

The product of its digits is 129600, while the sum is 35.

The square root of 1345543433 is about 36681.6498129514. The cubic root of 1345543433 is about 1103.9919508729.

Adding to 1345543433 its reverse (3343455431), we get a palindrome (4688998864).

The spelling of 1345543433 in words is "one billion, three hundred forty-five million, five hundred forty-three thousand, four hundred thirty-three".