Base | Representation |
---|---|
bin | 11001000100000000… |
… | …11100000111100011 |
3 | 1021201201210021222122 |
4 | 30202000130013203 |
5 | 210024043124103 |
6 | 10103100454455 |
7 | 654303242024 |
oct | 144200340743 |
9 | 37651707878 |
10 | 13455442403 |
11 | 5785279037 |
12 | 273624a42b |
13 | 1365855950 |
14 | 919042c4b |
15 | 53b417b38 |
hex | 32201c1e3 |
13455442403 has 8 divisors (see below), whose sum is σ = 14728026096. Its totient is φ = 12216794400.
The previous prime is 13455442393. The next prime is 13455442453. The reversal of 13455442403 is 30424455431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13455442403 - 210 = 13455441379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13455442453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8483093 + ... + 8484678.
It is an arithmetic number, because the mean of its divisors is an integer number (1841003262).
Almost surely, 213455442403 is an apocalyptic number.
13455442403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13455442403 is a deficient number, since it is larger than the sum of its proper divisors (1272583693).
13455442403 is a wasteful number, since it uses less digits than its factorization.
13455442403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16967845.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 13455442403 its reverse (30424455431), we get a palindrome (43879897834).
The spelling of 13455442403 in words is "thirteen billion, four hundred fifty-five million, four hundred forty-two thousand, four hundred three".
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