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13455681697 = 23585029639
BaseRepresentation
bin11001000100000010…
…10110100010100001
31021201202020110020101
430202001112202201
5210024123303242
610103105542401
7654305256463
oct144201264241
937652213211
1013455681697
1157854218a7
122736344a01
13136590a843
149190a6133
1553b4639b7
hex3220568a1

13455681697 has 4 divisors (see below), whose sum is σ = 14040711360. Its totient is φ = 12870652036.

The previous prime is 13455681691. The next prime is 13455681739. The reversal of 13455681697 is 79618655431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13455681697 - 211 = 13455679649 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13455681691) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292514797 + ... + 292514842.

It is an arithmetic number, because the mean of its divisors is an integer number (3510177840).

Almost surely, 213455681697 is an apocalyptic number.

It is an amenable number.

13455681697 is a deficient number, since it is larger than the sum of its proper divisors (585029663).

13455681697 is an equidigital number, since it uses as much as digits as its factorization.

13455681697 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 585029662.

The product of its digits is 5443200, while the sum is 55.

The spelling of 13455681697 in words is "thirteen billion, four hundred fifty-five million, six hundred eighty-one thousand, six hundred ninety-seven".

Divisors: 1 23 585029639 13455681697