Base | Representation |
---|---|
bin | 111110101011100001… |
… | …1001100011000110111 |
3 | 110212102211000002102222 |
4 | 1331113003030120313 |
5 | 4201132214104033 |
6 | 141500400152555 |
7 | 12503423605004 |
oct | 1752703143067 |
9 | 425384002388 |
10 | 134604441143 |
11 | 520a3774997 |
12 | 2210690875b |
13 | c901ab8413 |
14 | 672cc008ab |
15 | 377c1d2598 |
hex | 1f570cc637 |
134604441143 has 2 divisors, whose sum is σ = 134604441144. Its totient is φ = 134604441142.
The previous prime is 134604441119. The next prime is 134604441197. The reversal of 134604441143 is 341144406431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134604441143 - 212 = 134604437047 is a prime.
It is a super-3 number, since 3×1346044411433 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134604411143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67302220571 + 67302220572.
It is an arithmetic number, because the mean of its divisors is an integer number (67302220572).
Almost surely, 2134604441143 is an apocalyptic number.
134604441143 is a deficient number, since it is larger than the sum of its proper divisors (1).
134604441143 is an equidigital number, since it uses as much as digits as its factorization.
134604441143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 134604441143 its reverse (341144406431), we get a palindrome (475748847574).
The spelling of 134604441143 in words is "one hundred thirty-four billion, six hundred four million, four hundred forty-one thousand, one hundred forty-three".
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