Base | Representation |
---|---|
bin | 11001000100100111… |
… | …10100100011101001 |
3 | 1021202002100102120211 |
4 | 30202103310203221 |
5 | 210031343220431 |
6 | 10103401421121 |
7 | 654364362664 |
oct | 144223644351 |
9 | 37662312524 |
10 | 13460523241 |
11 | 5788129380 |
12 | 2737a9a7a1 |
13 | 1366914469 |
14 | 9199a66db |
15 | 53babd2b1 |
hex | 3224f48e9 |
13460523241 has 4 divisors (see below), whose sum is σ = 14684207184. Its totient is φ = 12236839300.
The previous prime is 13460523227. The next prime is 13460523277. The reversal of 13460523241 is 14232506431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13460523241 - 219 = 13459998953 is a prime.
It is a super-2 number, since 2×134605232412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13460523341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611841955 + ... + 611841976.
It is an arithmetic number, because the mean of its divisors is an integer number (3671051796).
Almost surely, 213460523241 is an apocalyptic number.
13460523241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13460523241 is a deficient number, since it is larger than the sum of its proper divisors (1223683943).
13460523241 is a wasteful number, since it uses less digits than its factorization.
13460523241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1223683942.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 13460523241 in words is "thirteen billion, four hundred sixty million, five hundred twenty-three thousand, two hundred forty-one".
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