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134619533048447 is a prime number
BaseRepresentation
bin11110100110111110001101…
…011100100111101001111111
3122122122111112201102201022222
4132212332031130213221333
5120121101300430022242
61154151205411155555
740232640344555666
oct3646761534475177
9578574481381288
10134619533048447
1139991906977837
12131222012a5bbb
135a1674ba32345
142535897a35ddd
151086b6a1515d2
hex7a6f8d727a7f

134619533048447 has 2 divisors, whose sum is σ = 134619533048448. Its totient is φ = 134619533048446.

The previous prime is 134619533048279. The next prime is 134619533048453. The reversal of 134619533048447 is 744840335916431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134619533048447 - 226 = 134619465939583 is a prime.

It is a super-2 number, since 2×1346195330484472 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134619533048447.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134619533018447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67309766524223 + 67309766524224.

It is an arithmetic number, because the mean of its divisors is an integer number (67309766524224).

Almost surely, 2134619533048447 is an apocalyptic number.

134619533048447 is a deficient number, since it is larger than the sum of its proper divisors (1).

134619533048447 is an equidigital number, since it uses as much as digits as its factorization.

134619533048447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 104509440, while the sum is 62.

The spelling of 134619533048447 in words is "one hundred thirty-four trillion, six hundred nineteen billion, five hundred thirty-three million, forty-eight thousand, four hundred forty-seven".