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1346221342543 = 71174323530813
BaseRepresentation
bin10011100101110001000…
…010110111111101001111
311202200211110221221021211
4103211301002313331033
5134024030130430133
62510240123235251
7166155422415160
oct23456102677517
94680743857254
101346221342543
11479a24940a40
12198aa6978b27
1399c4306327c
144922c101767
1525041bb7bcd
hex139710b7f4f

1346221342543 has 16 divisors (see below), whose sum is σ = 1680664859136. Its totient is φ = 1047591750240.

The previous prime is 1346221342541. The next prime is 1346221342559. The reversal of 1346221342543 is 3452431226431.

It is not a de Polignac number, because 1346221342543 - 21 = 1346221342541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1346221342496 and 1346221342505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1346221342541) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11708196 + ... + 11822617.

It is an arithmetic number, because the mean of its divisors is an integer number (105041553696).

Almost surely, 21346221342543 is an apocalyptic number.

1346221342543 is a deficient number, since it is larger than the sum of its proper divisors (334443516593).

1346221342543 is a wasteful number, since it uses less digits than its factorization.

1346221342543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23531574.

The product of its digits is 414720, while the sum is 40.

Adding to 1346221342543 its reverse (3452431226431), we get a palindrome (4798652568974).

The spelling of 1346221342543 in words is "one trillion, three hundred forty-six billion, two hundred twenty-one million, three hundred forty-two thousand, five hundred forty-three".

Divisors: 1 7 11 77 743 5201 8173 57211 23530813 164715691 258838943 1811872601 17483394059 122383758413 192317334649 1346221342543