Base | Representation |
---|---|
bin | 111110101100001001… |
… | …0100000110100000101 |
3 | 110212111021010111010111 |
4 | 1331120102200310011 |
5 | 4201203024443211 |
6 | 141502421553021 |
7 | 12504065416054 |
oct | 1753022406405 |
9 | 425437114114 |
10 | 134625234181 |
11 | 52104487019 |
12 | 22111875771 |
13 | c9061b87a9 |
14 | 673189439b |
15 | 377de3d421 |
hex | 1f584a0d05 |
134625234181 has 2 divisors, whose sum is σ = 134625234182. Its totient is φ = 134625234180.
The previous prime is 134625234169. The next prime is 134625234187. The reversal of 134625234181 is 181432526431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130417765956 + 4207468225 = 361134^2 + 64865^2 .
It is a cyclic number.
It is not a de Polignac number, because 134625234181 - 213 = 134625225989 is a prime.
It is a super-2 number, since 2×1346252341812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134625234187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67312617090 + 67312617091.
It is an arithmetic number, because the mean of its divisors is an integer number (67312617091).
Almost surely, 2134625234181 is an apocalyptic number.
It is an amenable number.
134625234181 is a deficient number, since it is larger than the sum of its proper divisors (1).
134625234181 is an equidigital number, since it uses as much as digits as its factorization.
134625234181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 40.
The spelling of 134625234181 in words is "one hundred thirty-four billion, six hundred twenty-five million, two hundred thirty-four thousand, one hundred eighty-one".
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