Base | Representation |
---|---|
bin | 111110101100001001… |
… | …1001100110000010001 |
3 | 110212111021110122000102 |
4 | 1331120103030300101 |
5 | 4201203101223121 |
6 | 141502425502145 |
7 | 12504100065560 |
oct | 1753023146021 |
9 | 425437418012 |
10 | 134625414161 |
11 | 5210459a267 |
12 | 22111941955 |
13 | c90624c6a4 |
14 | 67318ddbd7 |
15 | 377de7690b |
hex | 1f584ccc11 |
134625414161 has 4 divisors (see below), whose sum is σ = 153857616192. Its totient is φ = 115393212132.
The previous prime is 134625414139. The next prime is 134625414163. The reversal of 134625414161 is 161414526431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 161414526431 = 17 ⋅9494972143.
It is a cyclic number.
It is not a de Polignac number, because 134625414161 - 210 = 134625413137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134625414163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9616101005 + ... + 9616101018.
It is an arithmetic number, because the mean of its divisors is an integer number (38464404048).
Almost surely, 2134625414161 is an apocalyptic number.
It is an amenable number.
134625414161 is a deficient number, since it is larger than the sum of its proper divisors (19232202031).
134625414161 is an equidigital number, since it uses as much as digits as its factorization.
134625414161 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19232202030.
The product of its digits is 69120, while the sum is 38.
The spelling of 134625414161 in words is "one hundred thirty-four billion, six hundred twenty-five million, four hundred fourteen thousand, one hundred sixty-one".
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