Base | Representation |
---|---|
bin | 111110101100010100… |
… | …0101011000110101101 |
3 | 110212111200001122000111 |
4 | 1331120220223012231 |
5 | 4201211021343001 |
6 | 141503150300021 |
7 | 12504165662623 |
oct | 1753050530655 |
9 | 425450048014 |
10 | 134631043501 |
11 | 52107794709 |
12 | 221137b7611 |
13 | c907470a66 |
14 | 6732567513 |
15 | 377e6d9851 |
hex | 1f58a2b1ad |
134631043501 has 2 divisors, whose sum is σ = 134631043502. Its totient is φ = 134631043500.
The previous prime is 134631043483. The next prime is 134631043511. The reversal of 134631043501 is 105340136431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 133590981001 + 1040062500 = 365501^2 + 32250^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134631043501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134631043511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67315521750 + 67315521751.
It is an arithmetic number, because the mean of its divisors is an integer number (67315521751).
Almost surely, 2134631043501 is an apocalyptic number.
It is an amenable number.
134631043501 is a deficient number, since it is larger than the sum of its proper divisors (1).
134631043501 is an equidigital number, since it uses as much as digits as its factorization.
134631043501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 134631043501 its reverse (105340136431), we get a palindrome (239971179932).
The spelling of 134631043501 in words is "one hundred thirty-four billion, six hundred thirty-one million, forty-three thousand, five hundred one".
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