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134708405010745 = 526941681002149
BaseRepresentation
bin11110101000010000111110…
…101000010000000100111001
3122122221222221100201011122011
4132220100332220100010321
5120124030303140320440
61154300104213525521
740242234566022616
oct3650207650200471
9578858840634564
10134708405010745
1139a16571873465
12131374843438a1
135a21c42c37b97
142539cc8bb750d
15108911c4599ea
hex7a843ea10139

134708405010745 has 4 divisors (see below), whose sum is σ = 161650086012900. Its totient is φ = 107766724008592.

The previous prime is 134708405010721. The next prime is 134708405010757. The reversal of 134708405010745 is 547010504807431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 22084585931776 + 112623819078969 = 4699424^2 + 10612437^2 .

It is a cyclic number.

It is not a de Polignac number, because 134708405010745 - 25 = 134708405010713 is a prime.

It is a super-3 number, since 3×1347084050107453 (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13470840501070 + ... + 13470840501079.

It is an arithmetic number, because the mean of its divisors is an integer number (40412521503225).

Almost surely, 2134708405010745 is an apocalyptic number.

It is an amenable number.

134708405010745 is a deficient number, since it is larger than the sum of its proper divisors (26941681002155).

134708405010745 is an equidigital number, since it uses as much as digits as its factorization.

134708405010745 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26941681002154.

The product of its (nonzero) digits is 1881600, while the sum is 49.

The spelling of 134708405010745 in words is "one hundred thirty-four trillion, seven hundred eight billion, four hundred five million, ten thousand, seven hundred forty-five".

Divisors: 1 5 26941681002149 134708405010745